document.write( "Question 722403: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I put it back into the theorem it does not add up. I am concerned I am doing something wrong in the algebra part of this equation. Can you help?
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document.write( "Here is my formula: \n" );
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Algebra.Com's Answer #442734 by mananth(16946)![]() ![]() You can put this solution on YOUR website! I continue\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-7)(x+1)=0\r \n" ); document.write( "\n" ); document.write( "x= 7 Taking the positive value\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "5^2+12^2 \n" ); document.write( "25+144=169\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |