document.write( "Question 722375: cos(400)*sec(40)=?
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document.write( "sin(-pi/12)csc(25pi/12)=?
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document.write( "Sin(-20)/cos380 + tan(200)=? \n" );
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Algebra.Com's Answer #442730 by DrBeeee(684) ![]() You can put this solution on YOUR website! (1) cos(400)*sec(40) = cos(40)*(1/cos(40)) = cos(40)/cos(40) = 1 \n" ); document.write( "(2) sin(-180/12)*csc(25*180/12) = -sin(15)*(1/sin(15) = -1 \n" ); document.write( "(3) sin(-20)/cos(20) + tan(20) = -sin(20)/cos(20) + tan(20) = -tan(20) + \n" ); document.write( "tan(20) = 0 \n" ); document.write( "In the tan function of (3), I assume you meant 20, not 200. \n" ); document.write( " |