document.write( "Question 722277: The product of a two-digit number and the same number with its digits reversed is 3154. Find the sum of the two numbers. \n" ); document.write( "
Algebra.Com's Answer #442727 by DrBeeee(684)\"\" \"About 
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I know the answer is 38*83 = 3154
\n" ); document.write( "So the sum is 38+83 = 121
\n" ); document.write( "However I've been unable to derive it. Sorry.
\n" ); document.write( "I've got
\n" ); document.write( "(1) n1 = 10x + y and
\n" ); document.write( "(2) n2 = 10y + x
\n" ); document.write( "Therefore the sum is
\n" ); document.write( "(3) n1 + n2 = 11x + 11y or
\n" ); document.write( "(4) sum = 11(x+y)
\n" ); document.write( "But I can't come up with 3 and 8 for x and y.
\n" ); document.write( "Nor can I solve
\n" ); document.write( "(5) n1*n2 = 3154
\n" ); document.write( "We know that n1 (or n2) has to be greater than 32 in order to get a second two digit number for the product.
\n" ); document.write( "Maybe we can say both are greater than 32 which means x or y has to be 3, then try 33*33, 34*43, 35*53, 36*63, 37*73, 38*83, 39*93. Indeed
\n" ); document.write( "the answer appear, but mathematician can't accept trial and error. There's got to be a better way.
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