document.write( "Question 722277: The product of a two-digit number and the same number with its digits reversed is 3154. Find the sum of the two numbers. \n" ); document.write( "
Algebra.Com's Answer #442727 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! I know the answer is 38*83 = 3154 \n" ); document.write( "So the sum is 38+83 = 121 \n" ); document.write( "However I've been unable to derive it. Sorry. \n" ); document.write( "I've got \n" ); document.write( "(1) n1 = 10x + y and \n" ); document.write( "(2) n2 = 10y + x \n" ); document.write( "Therefore the sum is \n" ); document.write( "(3) n1 + n2 = 11x + 11y or \n" ); document.write( "(4) sum = 11(x+y) \n" ); document.write( "But I can't come up with 3 and 8 for x and y. \n" ); document.write( "Nor can I solve \n" ); document.write( "(5) n1*n2 = 3154 \n" ); document.write( "We know that n1 (or n2) has to be greater than 32 in order to get a second two digit number for the product. \n" ); document.write( "Maybe we can say both are greater than 32 which means x or y has to be 3, then try 33*33, 34*43, 35*53, 36*63, 37*73, 38*83, 39*93. Indeed \n" ); document.write( "the answer appear, but mathematician can't accept trial and error. There's got to be a better way. \n" ); document.write( " |