document.write( "Question 722341: How many liters of 70% acid solution must be mixed with 10% acid solution to get 480 L of a 60% acid solution \n" ); document.write( "
Algebra.Com's Answer #442721 by stanbon(75887)\"\" \"About 
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How many liters of 70% acid solution must be mixed with 10% acid solution to get 480 L of a 60% acid solution
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\n" ); document.write( "Using 2 variables:
\n" ); document.write( "Quantity Eq::: x + y = 480 L
\n" ); document.write( "Acid Eq::::: 70x+10y = 60*480
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "70x + 70y = 70*480
\n" ); document.write( "70x + 10y = 60*480
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\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "60y = 10*480
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\n" ); document.write( "y = 80 L (amt. of 10% solution needed)
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\n" ); document.write( "x = 400 L (amt. of 70% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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