document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722248>Question 722248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log base 4 of 5 + log base 4 of x = log 4 of 60 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442698 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I assume the right side is log base 4 of 60. I'll use L4 to represent log base 4. In this problem it doesn't matter what base of the log is, just that they are all the same.<BR>\n" );
document.write( "The left side is the sum of the logs of two numbers which is the same as the log of the product of the two numbers. So we have<BR>\n" );
document.write( "(1) L4(5*x) = L4(60) <BR>\n" );
document.write( "Take the inverse log of each side of (1) and we get<BR>\n" );
document.write( "(2) 5*x = 60 or<BR>\n" );
document.write( "(3) x = 12<BR>\n" );
document.write( "Let's check this.<BR>\n" );
document.write( "Is (L4(5) + L4(12) = L4(60))?<BR>\n" );
document.write( "Is (L10(5)/L10(4) + L10(12)/L10(4) = L10(60)/L10(4))?<BR>\n" );
document.write( "Is (L10(5) + L10(12) = L10(60))?<BR>\n" );
document.write( "Is (0.69897.. + 1.079... = 1.778...)?<BR>\n" );
document.write( "Is (1.778,,, = 1.778...)? Yes<BR>\n" );
document.write( "Answer: x equals 12. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );