document.write( "Question 63348: solve. a)x^2 - 2x=15 b)3x^2+19+1=0 c)1/4x +12 - 1/x^2-9=5/x-3
\n" ); document.write( "thank you so much. \n" ); document.write( "
Algebra.Com's Answer #44269 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
solve.
\n" ); document.write( ":
\n" ); document.write( "a)x^2 - 2x = 15
\n" ); document.write( ":
\n" ); document.write( "Subtract 15 to both sides, we have simple quadratic equation, we can factor:
\n" ); document.write( "x^2 - 2x - 15 = 0
\n" ); document.write( "(x - 5)(x + 3) = 0
\n" ); document.write( "x = +5
\n" ); document.write( "and
\n" ); document.write( "x = -3
\n" ); document.write( ":
\n" ); document.write( "Substituting either solution in the original equation will prove our solutions
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "b)3x^2 + 19 + 1 = 0
\n" ); document.write( "3x^2 + 20 = 0
\n" ); document.write( ":
\n" ); document.write( "Subtract 20 from both sides:
\n" ); document.write( "3x^2 = -20
\n" ); document.write( ":
\n" ); document.write( "Divide both sides by 3
\n" ); document.write( "x^2 = -20/3
\n" ); document.write( "x = +/- SqRt(-20/3)
\n" ); document.write( "x =+/- SqRt((5*4*-1)/3)
\n" ); document.write( ":
\n" ); document.write( "Extract the SqRt(4) and i (sqRt of -1):
\n" ); document.write( "x = +/- 2i*SqRt(5/3)
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "c)\"1%2F%284x%2B12%29+-+1%2F%28x%5E2-9%29+=++5%2F%28x-3%29\"
\n" ); document.write( ":
\n" ); document.write( "Factor where we can:
\n" ); document.write( "\"1%2F%284%28x%2B3%29%29+-+1%2F%28%28x-3%29%28x%2B3%29%29+=++5%2F%28x-3%29\"
\n" ); document.write( ":
\n" ); document.write( "We can see the common denominator is 4(x+3)(x-3), mult eq by that and we get:
\n" ); document.write( "1(x-3) - 4(1) = 4(x+3)*5
\n" ); document.write( "x - 3 - 4 = 20x + 60
\n" ); document.write( "x - 7 = 20x + 60
\n" ); document.write( "x - 20x = 60 + 7
\n" ); document.write( "-19x = + 67
\n" ); document.write( "x = -67/19\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );