document.write( "Question 63560: .the area of a square bookcase is 21 more than the perimeter. find the length of a side \n" ); document.write( "
Algebra.Com's Answer #44268 by joyofmath(189)\"\" \"About 
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.the area of a square bookcase is 21 more than the perimeter. find the length of a side\r
\n" ); document.write( "\n" ); document.write( "Let L = the side of the bookcase.
\n" ); document.write( "Let P = the perimeter of the bookcase.
\n" ); document.write( "Let A = the area of the bookcase.\r
\n" ); document.write( "\n" ); document.write( "Then, we know that:
\n" ); document.write( "\"A=P%2B21\"
\n" ); document.write( "\"A=L%5E2\"
\n" ); document.write( "\"P=4L\"\r
\n" ); document.write( "\n" ); document.write( "So, \"A=L%5E2=P%2B21\".
\n" ); document.write( "But, P=4L so \"A=L%5E2=4L%2B21\".
\n" ); document.write( "So, \"L%5E2+=+4L%2B21\".
\n" ); document.write( "Or, \"L%5E2-4L-21=0\".
\n" ); document.write( "This factors to \"%28L%2B3%29%28L-7%29=0\".
\n" ); document.write( "So, \"L=-3\" or \"L=7\".\r
\n" ); document.write( "\n" ); document.write( "The length can't be negative so \"L=7\".\r
\n" ); document.write( "\n" ); document.write( "Let's verify the answer.\r
\n" ); document.write( "\n" ); document.write( "If \"L=7\" then \"P=4%2A7=28\" and \"A=L%5E2=7%5E2=49\".
\n" ); document.write( "So, A is indeed 21 more than P.
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