document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=722212>Question 722212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a fraction, the numerator is 3 less than the denominator. If 1 is added to both the numerator and denominator, the value of the resulting fraction is 5/6. Find the original fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442678 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d = the original denominator of the fraction<BR>\n" );
document.write( "Then following the steps in the problem we get<BR>\n" );
document.write( "(1) (d-3)/d becomes<BR>\n" );
document.write( "(2) [(d-3)+1]/(d+1) = 5/6 or<BR>\n" );
document.write( "(3) (d-2)/(d+1) = 5/6, and by cross multiplying we get<BR>\n" );
document.write( "(4) 6*(d-2) = 5*(d+1) or<BR>\n" );
document.write( "(5) 6d - 12 = 5d + 5 or<BR>\n" );
document.write( "(6) d = 17<BR>\n" );
document.write( "Check d using (2)<BR>\n" );
document.write( "Is ([17-3+1]/(17+1) = 5/6)?<BR>\n" );
document.write( "Is (15/18 = 5/6)?<BR>\n" );
document.write( "Is (5/6 = 5/6)? Yes<BR>\n" );
document.write( "Therefore the original numerator is three less than d or 14.<BR>\n" );
document.write( "Answer: The original fraction is 14/17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );