document.write( "Question 721985: identify the conic by writing the equation in standard form (4y^2)-(2x^2)-4y+8x-15=0 \n" ); document.write( "
Algebra.Com's Answer #442596 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
The process needed is Complete the Square, and you do it for the x and for the y.\r
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\n" ); document.write( "\n" ); document.write( "\"%284y%5E2%29-%282x%5E2%29-4y%2B8x-15=0\"
\n" ); document.write( "\"4y%5E2-4y-2x%5E2%2B8x-15=0\"
\n" ); document.write( "\"4%28y%5E2-y%29-2%28x%5E2-4x%29-15=0\"
\n" ); document.write( "The square term to use for y is \"%281%2F2%29%5E2=1%2F4\" and the square term to use for x is \"%284%2F2%29%5E2=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"4%28y%5E2-y%2B1%2F4%29-4%281%2F4%29-2%28x%5E2-4x%2B4%29-%28-2%29%284%29=15\", combined a step as well as added and subtracted the appropriate square quantities and their results.\r
\n" ); document.write( "\n" ); document.write( "\"4%28y-1%2F2%29%5E2-2%28x-2%29%5E2-1%2B8=15\"
\n" ); document.write( "\"4%28y-1%2F2%29%5E2-2%28x-2%29%5E2=15-7\"
\n" ); document.write( "\"4%28y-1%2F2%29%5E2-2%28x-2%29%5E2=8\", now divide each side by 8
\n" ); document.write( "\"highlight%28%281%2F2%29%28y-1%2F2%29%5E2-%281%2F4%29%28x-2%29%5E2=1%29\"\r
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\n" ); document.write( "\n" ); document.write( "HYPERLOBA.\r
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\n" ); document.write( "\n" ); document.write( "Note that you might want to see it written as
\n" ); document.write( "\"highlight%28%28%28y-1%2F2%29%5E2%29%2F2+-%28%28x-2%29%5E2%29%2F4+=1%29\"
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