document.write( "Question 722011: passing through (6, -3), and perpendicular to the line whose equation is x - 3y - 2 = 0 the equation of the line in point slope form is \n" ); document.write( "
Algebra.Com's Answer #442587 by mananth(16946)\"\" \"About 
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-3 y = -1 x + 2
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 1/ 3 x + - 2/3
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -3
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be -3
\n" ); document.write( "
\n" ); document.write( "m= -3 ,point ( 6 , -3 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-3 = -18 + b
\n" ); document.write( "b= 15
\n" ); document.write( "m= -3
\n" ); document.write( "The required equation is y = -3 x + 15
\n" ); document.write( "m.ananth@hotmail.ca
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