document.write( "Question 721995: a bakery delivery truck leaves the bakery at 5:00am each morning on its 144 mile route.one day the driver gets a late start and does not leve the bakery until 5:20am. to finish her route on time the driver drives 4 miles per hour faster than usual.at what speed does she usually drive ? \n" ); document.write( "
Algebra.Com's Answer #442581 by mananth(16946)\"\" \"About 
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usual speed be x\r
\n" ); document.write( "\n" ); document.write( " today's speed = x+4\r
\n" ); document.write( "\n" ); document.write( "difference in time = 1/3 hours ( 20 min)\r
\n" ); document.write( "\n" ); document.write( "Usual time - today's time = 1/3\r
\n" ); document.write( "\n" ); document.write( "\"144%2Fx+-+144%2F%28x%2B4%29+=+1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "multiply equation by 3x(x+4)\r
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\n" ); document.write( "\n" ); document.write( "\"144%2A3%28x%2B4%29-144%2A3%2Ax=+x%28x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "432x+1728-432x=x^2+4x\r
\n" ); document.write( "\n" ); document.write( "x^2+4x-1728=0\r
\n" ); document.write( "\n" ); document.write( "solve this you will get the usual speed which is 39.62 \r
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