document.write( "Question 721995: a bakery delivery truck leaves the bakery at 5:00am each morning on its 144 mile route.one day the driver gets a late start and does not leve the bakery until 5:20am. to finish her route on time the driver drives 4 miles per hour faster than usual.at what speed does she usually drive ? \n" ); document.write( "
Algebra.Com's Answer #442581 by mananth(16946)![]() ![]() You can put this solution on YOUR website! usual speed be x\r \n" ); document.write( "\n" ); document.write( " today's speed = x+4\r \n" ); document.write( "\n" ); document.write( "difference in time = 1/3 hours ( 20 min)\r \n" ); document.write( "\n" ); document.write( "Usual time - today's time = 1/3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply equation by 3x(x+4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "432x+1728-432x=x^2+4x\r \n" ); document.write( "\n" ); document.write( "x^2+4x-1728=0\r \n" ); document.write( "\n" ); document.write( "solve this you will get the usual speed which is 39.62 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |