document.write( "Question 721997: A rectangle is four times as long as it is wide. If the area of the rectangle is 1600 cm squared, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #442579 by MithrilKnights(8)\"\" \"About 
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We let the length be 4x\r
\n" ); document.write( "\n" ); document.write( "Let the width be x\r
\n" ); document.write( "\n" ); document.write( "So, 4x*x = 1600 cm^2\r
\n" ); document.write( "\n" ); document.write( "So, 4x^2 = 1600\r
\n" ); document.write( "\n" ); document.write( "So, x^2 = 400 and x=20\r
\n" ); document.write( "\n" ); document.write( "Therefore, plugging them into the previous lengths we get,\r
\n" ); document.write( "\n" ); document.write( "4x = 80\r
\n" ); document.write( "\n" ); document.write( "x = 20\r
\n" ); document.write( "\n" ); document.write( "So the dimensions are 80 x 20.\r
\n" ); document.write( "\n" ); document.write( "And 80 x 20 = 1600, which works
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