document.write( "Question 721347: If log20 = x then, Find the exact value of B such that log B = x + 3 \n" ); document.write( "
Algebra.Com's Answer #442546 by jsmallt9(3758)\"\" \"About 
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log(20) = x
\n" ); document.write( "log(B) = x + 3
\n" ); document.write( "One solution:
\n" ); document.write( "Substitute for x:
\n" ); document.write( "log(B) = log(20) + 3
\n" ); document.write( "Subtract log(20):
\n" ); document.write( "log(B) - log(20) = 3
\n" ); document.write( "Using a property of logarithms, log(p) - log(q) = log(p/q), to combine the two logs:
\n" ); document.write( "log(B/20) = 3
\n" ); document.write( "Rewrite in exponential form. In general, log(p) = n is equivalent to p = 10^n. Using this pattern on our equation we get:
\n" ); document.write( "B/20 = 10^3
\n" ); document.write( "which simplifies to:
\n" ); document.write( "B/20 = 1000
\n" ); document.write( "Multiply by 20:
\n" ); document.write( "B = 20000
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