document.write( "Question 721839: The sum of three whole numbers between 0 and 10 is 16. The product of the numbers 120. The sum of the two smaller numbers equals the greatest number. What are the the numbers? \n" ); document.write( "

Algebra.Com's Answer #442532 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "If the product of the three numbers is 120, since 120 ends in 0, one of the three numbers must be either 5 or 10. If one of the numbers is 10, then the product of the other 2 is 12 and they must add up to 10. No such numbers. So one of the numbers has to be 5. Dividing 120 by 5 is 24. The two single digit factors of 24 are either 4 and 6 or 3 and 8. No combination of 4, 5, and 6 exists where the sum of two of the digits is the third. But 3, 5, and 8 work because 3 plus 5 is 8. Recap: 3 + 5 + 8 = 16. 3 * 5 * 8 = 120. and 3 + 5 = 8. All conditions satisfied.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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