document.write( "Question 721770: A chemist uses an 80% acid solution and a 30% acid solution to make 200 liters of a 60% acid solution. How much of the 30% solution should be used.
\n" ); document.write( "A. 60 L
\n" ); document.write( "B. 80 L
\n" ); document.write( "C. 100 L
\n" ); document.write( "D. 120 L
\n" ); document.write( "

Algebra.Com's Answer #442497 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Assuming all concentrations are %w/v, you would have these:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x for 30% acid, y for 80% acid,\r
\n" ); document.write( "\n" ); document.write( "\"%2830x%2B80y%29%2F200=60\" and \"x%2By=200\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for x and y.
\n" ); document.write( "
\n" );