document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=721621>Question 721621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "How many ounces of pure copper must a goldsmith add to 240 ounces of an alloy containing 40% copper to obtain an alloy containing 60% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442452 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .40*240+X=.60(240+X)<BR>\n" );
document.write( "96+X=144+.60X<BR>\n" );
document.write( "X-.60X=144-96<BR>\n" );
document.write( ".40X=48<BR>\n" );
document.write( "X=48/.40<BR>\n" );
document.write( "X=120 OZ OF PURE COPPER IS NEEDED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".40*240+120=.60(240+120)<BR>\n" );
document.write( "96+120=.60*360<BR>\n" );
document.write( "216=216 </SPAN>\n" );
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