document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=721589>Question 721589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! I would like some help to solve this problem:\r<BR>\n" );
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document.write( "A passenger train traveling at 50 kph leaves a station 6 hours after a freight train and overtakes it in 4 hours. Find the rate of the freight train.\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442445 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> freight train speed = x<BR>\n" );
document.write( "passenger train speed = 50\r<BR>\n" );
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document.write( "freight train has traveled 6x miles before passenger train starts.\r<BR>\n" );
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document.write( "Catch up speed = 50-x\r<BR>\n" );
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document.write( "Catch up distance = 6x\r<BR>\n" );
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document.write( "time = 4\r<BR>\n" );
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document.write( "t= d/r\r<BR>\n" );
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document.write( "4= 6x/(50-x)\r<BR>\n" );
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document.write( "4(50-x) =6x\r<BR>\n" );
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document.write( "200-4x=6x\r<BR>\n" );
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document.write( "10x= 200<BR>\n" );
document.write( "x= 20mph speed of freight train\r<BR>\n" );
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