document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=721508>Question 721508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I will like to know how i can solve the following word problem using two linear equations containing two unknowns.<BR>\n" );
document.write( "Paul  has 40 dimes and quarters worth $8.50. How many of each coin does he have?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442383 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> dimes -----x<BR>\n" );
document.write( "quarters --------y\r<BR>\n" );
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document.write( "x+y =40..............(1)<BR>\n" );
document.write( "10x+25y=850...........(2)\r<BR>\n" );
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document.write( "multiply (1) by -10 and add this equation to (2)<BR>\n" );
document.write( "-10x-10y=-400\r<BR>\n" );
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document.write( "15y=450<BR>\n" );
document.write( "y= 30\r<BR>\n" );
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document.write( "so x=10\r<BR>\n" );
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document.write( "dimes -----x----------10<BR>\n" );
document.write( "quarters --------y-----30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );