document.write( "Question 721146: (n)^2+(2n-1)^2=(2n+1)^2 \n" ); document.write( "
Algebra.Com's Answer #442265 by checkley79(3341)\"\" \"About 
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(n)^2+(2n-1)^2=(2n+1)^2
\n" ); document.write( "N^2+4N^2-4N+1=4N^2+4N+1
\n" ); document.write( "N^2-4N-4N=0
\n" ); document.write( "N^2-8N=0
\n" ); document.write( "N(N-8)=0
\n" ); document.write( "N=0 ANS
\n" ); document.write( "N-8=0
\n" ); document.write( "N=8 ANS.
\n" ); document.write( "PROOFS:
\n" ); document.write( "0^2+(2*0-1)^2=(2*0+1)^2
\n" ); document.write( "0+-1^2=1^2
\n" ); document.write( "1=1
\n" ); document.write( "8^2+(2*8-1)^2=(2*8+1)^2
\n" ); document.write( "64+(16-1)^2=(16+1)^2
\n" ); document.write( "64+15^2=17^2
\n" ); document.write( "64+225=289
\n" ); document.write( "289=289
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