document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=721139>Question 721139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of the triangle shown on the right with base 1 3/4 yards and height 4/5 yard. (hint: the area of a triangle equals half the product of its base and height.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442260 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the area of the triangle shown on the right with base 1 3/4 yards and height 4/5 yard. (hint: the area of a triangle equals half the product of its base and height.)<BR>\n" );
document.write( "(1/2)(base)(height)<BR>\n" );
document.write( "(1/2)(1 3/4)(4/5)<BR>\n" );
document.write( "(1/2)(4/4+3/4)(4/5)<BR>\n" );
document.write( "(1/2)(7/4)(4/5)<BR>\n" );
document.write( "(7/8)(4/5)<BR>\n" );
document.write( "(7/2)(1/5)<BR>\n" );
document.write( "7/10 square yards </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );