document.write( "Question 721008: write the equation of a hyperbola in standard form whose center is (-2, -4), a focus at (-2, 6), and eccentricity of 5/4. \n" ); document.write( "
Algebra.Com's Answer #442227 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! write the equation of a hyperbola in standard form whose center is (-2, -4), a focus at (-2, 6), and eccentricity of 5/4. \n" ); document.write( "*** \n" ); document.write( "Given hyperbola has a vertical transverse axis. (From given center and focus data, y-coordinates change but x-coordinates do not.) \n" ); document.write( "Its standard form of equation: \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (-2,-4) \n" ); document.write( "c=10 (-4 to 6) (distance from center to focus on vertical transverse axis) \n" ); document.write( "c^2=100 \n" ); document.write( "eccentricity=5/4=c/a \n" ); document.write( "a=4c/5=40/5=9 \n" ); document.write( "a^2=81 \n" ); document.write( "c^2=a^2+b^2 \n" ); document.write( "b^2=c^2-a^2=100-81=19 \n" ); document.write( "Equation of given hyperbola: \n" ); document.write( " |