document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=721129>Question 721129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please show the steps for this and give the ordered pair? use the method of substitution to solve the system of linear equations.<BR>\n" );
document.write( "2x-y=4<BR>\n" );
document.write( "7x-3y=16  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #442215 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=442215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the first equation by 3:  3*(2x-y=4) = (6x-3y=12)<P><BR>\n" );
document.write( "Subtract that equation from the second equation:  7x-3y=16 - (6x-3y=12) becomes 7x-6x -3y + 3y = 16-12 ---> x=4<P><BR>\n" );
document.write( "Substitute that into either equation (try the first): 2(4) - y = 4 ---> 8 - y = 4 ---> 4=y<P><BR>\n" );
document.write( "The ordered pair solution is (4,4)<BR>\n" );
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