document.write( "Question 721037: A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16 kg mixture was worth $6.70/kg. How many kilograms of each type were used. Algebra must be used. Thank You. \n" ); document.write( "

Algebra.Com's Answer #442203 by josgarithmetic(39618) $\"\"$ $\"About$

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u = kgs of low priced $6/kg
\n" ); document.write( "v = kgs of high priced $8.80/kg
\n" ); document.write( "M = 16 kg of mixture
\n" ); document.write( "T = $6.70/kg of mixture
\n" ); document.write( "L = $6/kg
\n" ); document.write( "H = $8.80/kg
\n" ); document.write( "The unknown variables to solve for and values to find are u and v.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"highlight%28%28Lu%2BHv%29%2FM=T%29\"$ and $\"highlight%28u%2Bv=M%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve symbolically for u and v, and then substitute given values to find values of u and v. \n" ); document.write( "

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