document.write( "Question 720981: triangle QRS has vertices at Q(2,6),R(-3,1), and S(6,2). determine the perimeter of the triangle. i just need help how to do it. thnxs \n" ); document.write( "

Algebra.Com's Answer #442125 by fcabanski(1391) $\"\"$ $\"About$

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The perimeter of a triangle is the sum of the side lengths. The distance formula gives the distance between points on a coordinate plane. The distance between pairs of points (vertices) in a triangle is the side length.

\n" ); document.write( "The distance formula is the square root of the difference between the y values squared plus the difference between the x values squared.

\n" ); document.write( "d= $\"sqrt%28%28y%282%29-y%281%29%29%5E2+%2B+%28x%282%29-x%281%29%29%5E2%29\"$

\n" ); document.write( "The triangle has three sides: QR, RS and SQ. Find the lengths of those sides, then add them to find the perimeter.

\n" ); document.write( "QR length = d = $\"sqrt%28%281-6%29%5E2+%2B+%28-3-2%29%5E2%29+=+sqrt%2850%29\"$

\n" ); document.write( "RS length = d = $\"sqrt%28%282-1%29%5E2+%2B+%286-%28-3%29%29%5E2%29+=+sqrt%2882%29\"$

\n" ); document.write( "SQ length = d = $\"sqrt%28%286-2%29%5E2+%2B+%282-6%29%5E2%29+=+sqrt%2832%29\"$

\n" ); document.write( "Their sum is approximately 21.78\r
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