document.write( "Question 720895: A man travels from his home to visit his brother who live 250km away. He travels at 100km/h\r
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\n" ); document.write( "\n" ); document.write( "A) How long did the Journey take?\r
\n" ); document.write( "\n" ); document.write( "B) If he returns at x km/h, how long does it take?\r
\n" ); document.write( "\n" ); document.write( "C) If the return trip took 50 minutes less, at what speed was he traveling on the return journey?
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Algebra.Com's Answer #442053 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+d+=+r%2At+\"
\n" ); document.write( "(A)
\n" ); document.write( "\"+t+=+d%2Fr+\"
\n" ); document.write( "\"+t+=+250+%2F+100+\"
\n" ); document.write( "\"+t+=+2.5+\" hrs
\n" ); document.write( "(B)
\n" ); document.write( "\"+2.5+%2B+d%2Fr+\"
\n" ); document.write( "\"+2.5+%2B+250%2Fx+\"
\n" ); document.write( "(C)
\n" ); document.write( "\"+250%2Fx+=+2.5+-+50%2F60+\" ( note: 50 min = 50/60 hrs )
\n" ); document.write( "\"+250%2Fx+=+2.5+-+5%2F6+\"
\n" ); document.write( "Multiply both sides by \"+6x+\"
\n" ); document.write( "\"+6%2A250+=+2.5%2A6x+-+5x+\"
\n" ); document.write( "\"+15x+-+5x+=+1500+\"
\n" ); document.write( "\"+10x+=+1500+\"
\n" ); document.write( "\"+x+=+150+\"
\n" ); document.write( "His speed returning was 150 km/hr
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