document.write( "Question 720881: 10 liters of a solution has a concentration of 5% sodium hydroxide. It is mixed with 5 liters of a different solution, which has a concentration of 8% sodium hydroxide. What is the new concentration of sodium hydroxide in the solution? \n" ); document.write( "
Algebra.Com's Answer #442039 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The amount of sodium hydroxide in the new solution will be 5% of 10 liters plus 8% of 5 liters. The amount of new solution is predictably near 10+5 liters. The result wanted in amount of pure sodium hydroxide divided by amount of the resulting solution, multiplied by 100 in case decimal fractions were used. The concentration would be assumed % weight per volume. \n" ); document.write( " |