document.write( "Question 720870: tan3x = sqrt 3
\n" ); document.write( "solve for [0,2pi] \n" ); document.write( "

Algebra.Com's Answer #442032 by lwsshak3(11628) $\"\"$ $\"About$

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tan3x = sqrt 3
\n" ); document.write( "solve for [0,2pi]
\n" ); document.write( "tan 3x=√3
\n" ); document.write( "3x=π/3, 4π/3
\n" ); document.write( "x=π/9, 4π/9 \n" ); document.write( "

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