document.write( "Question 720867: 2sin^2x-5sinx=-3 \n" ); document.write( "
Algebra.Com's Answer #442031 by lwsshak3(11628)\"\" \"About 
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2sin^2x-5sinx=-3
\n" ); document.write( "2sin^2x-5sinx+3=0
\n" ); document.write( "(2sinx-3)(sinx-1)=0
\n" ); document.write( "2sinx-3=0
\n" ); document.write( "sinx=3/2 (reject, -1 ≤ sinx ≤ 1)
\n" ); document.write( "or
\n" ); document.write( "sinx-1=0
\n" ); document.write( "sinx=1
\n" ); document.write( "x=π/2
\n" ); document.write( "
\n" );