document.write( "Question 720876: 2 planes took off from Milwaukee. First plane is traveling 3 times as fast as the second plane. After traveling the same direction for 2 hours they are 368 miles apart. Whats the average speed of each plane. \n" ); document.write( "
Algebra.Com's Answer #442028 by josgarithmetic(39617)\"\" \"About 
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Which Plane___________rate______________time________________distance
\n" ); document.write( "First Fast____________3r________________2___________________3r*2
\n" ); document.write( "Second Slower__________r________________2___________________r*2
\n" ); document.write( "Their Difference________________________2___________________368\r
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\n" ); document.write( "\n" ); document.write( "One plane went farther than the other creating distance between them of 368 miles. The difference from \"distance\" column expressions is \"highlight%283r%2A2-r%2A2=368%29\". Obviously showing the subtraction of the slower plane distance from the faster plane distance is most sensible. Solve for r. Compute 3r.\r
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\n" ); document.write( "\n" ); document.write( "Note, equation simplifies to \"4r=368\".
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