document.write( "Question 63513This question is from textbook Precalculus
\n" ); document.write( ": The line $\"x+-+2y+=+-4\"$ is tangent to the circle at (0,2). the line $\"y+=+2x+-+7\"$ is tangent to the circle at (3,-1). Find the center of the circle \n" ); document.write( "

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The line(L1 SAY) x - 2y = -4 is tangent to the circle at (P SAY )(0,2). the line(l2 SAY) y = 2x - 7 is tangent to the circle at(Q SAY) (3,-1). Find the center of the circle
\n" ); document.write( "LET THE CENTER OF THE CIRCLE BE (C SAY) (H,K)
\n" ); document.write( "SLOPE OF CP *SLOPE OF L1 =-1...SINCE RADIUS AT POINT OF CONTACT IS PERPENDICULAR TO TANGENT
\n" ); document.write( "(K-2)/(H)][1/2]=-1
\n" ); document.write( "K-2 = -2H.........
\n" ); document.write( "2H+K = 2.............1\r
\n" ); document.write( "\n" ); document.write( " SIMILARLY SLOPE OF CQ *SLOPE OF L2 =-1...SINCE RADIUS AT POINT OF CONTACT IS PERPENDICULAR TO TANGENT
\n" ); document.write( "(K+1)/(H-3)][2]=-1
\n" ); document.write( "2K+2 = -H+3.........
\n" ); document.write( "H+2K = 1.............2
\n" ); document.write( "2*EQN.1 - EQN.2
\n" ); document.write( "3H=3
\n" ); document.write( "H = 1
\n" ); document.write( "K= 2-(2*1)=0
\n" ); document.write( "CENTER IS (1,0) \n" ); document.write( "

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