document.write( "Question 720803: how much pure antifreeze must be added to 20 L of a solution thaT IS 60% antifreeze to make a solution that is 80% antifreeze \n" ); document.write( "

Algebra.Com's Answer #441995 by Edwin McCravy(20056) $\"\"$ $\"About$

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how much pure antifreeze must be added to 20 L of a solution thaT IS 60% antifreeze to make a solution that is 80% antifreeze
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document.write( "                                    Percentage           Liters of         \r\n" );
document.write( "                   Liters of        expressed as      pure antifreeze\r\n" );
document.write( "                    liquid           a decimal          in the liquid               \r\n" );
document.write( "first solution         20              .60               .60(20)\r\n" );
document.write( "added solution          x             1.00               1.00x  \r\n" );
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document.write( "final solution        20+x             .80              .80(20+x)\r\n" );
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document.write( "The equation comes from:\r\n" );
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document.write( "                  .60(20) + 1.00x = .80(20+x)\r\n" );
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document.write( "Solve that and get x = 20 liters.\r\n" );
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document.write( "Edwin

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