document.write( "Question 720818: Given F(x)=-2x^2+6x-1. Find the vertex and the axis of symmetry, and graph the function.\r
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document.write( "So far I've graphed the function. I think the vertex is 3/2,7/2, but I'm not sure. I need help finding the axis of symmetry please, thanks! \n" );
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Algebra.Com's Answer #441992 by stanbon(75887) ![]() You can put this solution on YOUR website! Given F(x)=-2x^2+6x-1. Find the vertex and the axis of symmetry, and graph the function. \n" ); document.write( "So far I've graphed the function. I think the vertex is 3/2,7/2, but I'm not sure. I need help finding the axis of symmetry please, thanks! \n" ); document.write( "----- \n" ); document.write( "Vertex occurs at x = -b/(2a) = -6/(2*-2) = 3/2 \n" ); document.write( "---- \n" ); document.write( "f(3/2) = -2(3/2)^2+6(3/2)-1 = 7/2 \n" ); document.write( "-------- \n" ); document.write( "So, you are correct. \n" ); document.write( "----- \n" ); document.write( "Since the parabola opens downward the the vertex is at x = 3/2 \n" ); document.write( "----- \n" ); document.write( "Axis of symmetry is x = 3/2 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " |