document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63482>Question 63482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 6 more than another.  If the sum of the smaller number and 3 times the larger number is 34, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44194 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the smaller number<BR>\n" );
document.write( "Then x+6=the larger number\r<BR>\n" );
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document.write( "We are told that the sum of the smaller number (x) and three times the larger number 3(x+6) equals 34.  So, our equation to solve would be:\r<BR>\n" );
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document.write( "x+3(x+6)=34 simplifying<BR>\n" );
document.write( "x+3x+18=34<BR>\n" );
document.write( "4x=34-18<BR>\n" );
document.write( "4x=16<BR>\n" );
document.write( "x=4 smaller number<BR>\n" );
document.write( "x+6=4+6=10 larger number\r<BR>\n" );
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document.write( "Hope this helps.  Have a nice holiday season----ptaylor </SPAN>\n" );
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