document.write( "Question 720624: Suppose a person invest a total of invests a total of $12,000 in two accounts. One account earns 5% annually, and the other earns 6% annually. If the total interest earned from both accounts in a year is $690, how much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #441907 by mananth(16946)\"\" \"About 
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Part I 5.00% per annum ---x *
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 12000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "5.00% x + 6.00% y= 690
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5 x + 6 y= 69000.00 --------2
\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
\n" ); document.write( "-5 x -5 y= -60000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 1 y= 9000
\n" ); document.write( "divide by 1
\n" ); document.write( " y = 9000 -
\n" ); document.write( "Part I 5.00% $ 3000
\n" ); document.write( "Part II 6.00% $ 9000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "3000 --------- 5.00% ------- 150.00
\n" ); document.write( "9000 ------------- 6.00% ------- 540.00
\n" ); document.write( "Total -------------------- 690.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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