document.write( "Question 720502: Sec^2x=4 \n" ); document.write( "
Algebra.Com's Answer #441893 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Sec^2x=4 \n" ); document.write( "secx=2=1/cosx \n" ); document.write( "cosx=1/2 \n" ); document.write( "x=π/3 or 60º \n" ); document.write( " |