document.write( "Question 720502: Sec^2x=4 \n" ); document.write( "
Algebra.Com's Answer #441893 by lwsshak3(11628)\"\" \"About 
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Sec^2x=4
\n" ); document.write( "secx=2=1/cosx
\n" ); document.write( "cosx=1/2
\n" ); document.write( "x=π/3 or 60º
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