document.write( "Question 720546: Need help with the following please.\r
\n" ); document.write( "\n" ); document.write( "Solve. Check for extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "square root 3x + 2 - square root 2x + 7 = 0 (dont know how to type sq. root symbol or exponets)\r
\n" ); document.write( "\n" ); document.write( "So far I have the following:\r
\n" ); document.write( "\n" ); document.write( "sq. root 3x + 2 = sq. root 2x + 7\r
\n" ); document.write( "\n" ); document.write( "9x to the second power + 4 = 4x to the second power + 49\r
\n" ); document.write( "\n" ); document.write( "5x to the second power - 45\r
\n" ); document.write( "\n" ); document.write( "Don't know what to do from here.
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Algebra.Com's Answer #441867 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
square root 3x + 2 - square root 2x + 7 = 0\r
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\n" ); document.write( "\n" ); document.write( "Without the braces for rendering,
\n" ); document.write( "sqrt(3x+2)-sqrt(2x+7)=0\r
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\n" ); document.write( "\n" ); document.write( "As rendered, triple curly braces at left and right,
\n" ); document.write( "\"sqrt%283x%2B2%29-sqrt%282x%2B7%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%283x%2B2%29=%2Bsqrt%282x%2B7%29\" and then square both sides.
\n" ); document.write( "\"3x%2B2=2x%2B7\"
\n" ); document.write( "\"x=5\".
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