document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=720543>Question 720543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	The length of a rectangle is 16 centimeters, and the diagonal of the rectangle is 20 centimeters long. What is the perimeter of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441864 by </B><A HREF=/tutors/aboutme.mpl?userid=ramsinaaa><B>ramsinaaa(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramsinaaa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use pythagorean theorem to solve for the width of the rectangle.\r<BR>\n" );
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document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "16^2+b^2=20^2<BR>\n" );
document.write( "256+b^2=400<BR>\n" );
document.write( "b^2=144<BR>\n" );
document.write( "b=12\r<BR>\n" );
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document.write( "length=16 width=12\r<BR>\n" );
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document.write( "2(length+width)=perimeter<BR>\n" );
document.write( "2(16+12)<BR>\n" );
document.write( "2(28)<BR>\n" );
document.write( "perimeter=56 </SPAN>\n" );
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