document.write( "Question 720429: In a labatory, a culture increases from 30 to 195 organisms in 5 hours. What is the hourly growth rate in the growth formula y=a(1+r)^t \n" ); document.write( "
Algebra.Com's Answer #441825 by nerdybill(7384) You can put this solution on YOUR website! In a labatory, a culture increases from 30 to 195 organisms in 5 hours. What is the hourly growth rate in the growth formula y=a(1+r)^t \n" ); document.write( ". \n" ); document.write( "y=a(1+r)^t \n" ); document.write( "The problem gives us: \n" ); document.write( "y as 195 \n" ); document.write( "a as 30 \n" ); document.write( "t as 5 \n" ); document.write( ". \n" ); document.write( "195=30(1+r)^5 \n" ); document.write( "195/30 = (1+r)^5 \n" ); document.write( "6.5 = (1+r)^5 \n" ); document.write( "6.5^(1/5) = 1+r \n" ); document.write( "6.5^(.2) = 1+r \n" ); document.write( "6.5^(.2) - 1 = r \n" ); document.write( "1.454 - 1 = r \n" ); document.write( "0.454 = r \n" ); document.write( "45.4% = r \n" ); document.write( " \n" ); document.write( " |