document.write( "Question 720429: In a labatory, a culture increases from 30 to 195 organisms in 5 hours. What is the hourly growth rate in the growth formula y=a(1+r)^t \n" ); document.write( "
Algebra.Com's Answer #441825 by nerdybill(7384)\"\" \"About 
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In a labatory, a culture increases from 30 to 195 organisms in 5 hours. What is the hourly growth rate in the growth formula y=a(1+r)^t
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\n" ); document.write( "y=a(1+r)^t
\n" ); document.write( "The problem gives us:
\n" ); document.write( "y as 195
\n" ); document.write( "a as 30
\n" ); document.write( "t as 5
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\n" ); document.write( "195=30(1+r)^5
\n" ); document.write( "195/30 = (1+r)^5
\n" ); document.write( "6.5 = (1+r)^5
\n" ); document.write( "6.5^(1/5) = 1+r
\n" ); document.write( "6.5^(.2) = 1+r
\n" ); document.write( "6.5^(.2) - 1 = r
\n" ); document.write( "1.454 - 1 = r
\n" ); document.write( "0.454 = r
\n" ); document.write( "45.4% = r
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