document.write( "Question 720399: If Edna leaves now and drives at 30 mi/h, she can reach Athens just in time for her night class. On the other hand, if she eats a snack and leaves in 20 min, she has to drive 45 mi/h ti make it to her class on time. How far away is Athens?\r
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document.write( "I do not even know how to set this problem up. \n" );
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Algebra.Com's Answer #441813 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If Edna leaves now and drives at 30 mi/h, she can reach Athens just in time for her night class. \n" ); document.write( " On the other hand, if she eats a snack and leaves in 20 min, she has to drive 45 mi/h ti make it to her class on time. \n" ); document.write( " How far away is Athens? \n" ); document.write( ": \n" ); document.write( "Change 20 min to 1/3 hr \n" ); document.write( ": \n" ); document.write( "Let d = distance to the class \n" ); document.write( ": \n" ); document.write( "Write a time equation \n" ); document.write( " \n" ); document.write( "multiply by 90 to clear the denominators \n" ); document.write( "3d = 2d + 30 \n" ); document.write( "3d - 2d = 30 \n" ); document.write( "d = 30 mi to class \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this; find the driving time at each speed \n" ); document.write( "30/30 = 1 hr to get to class on time \n" ); document.write( "30/45 = 2/3 hrs which allows 1/3 hr for a snack\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |