document.write( "Question 8049: The perimeter of a rectangle is 150 feet. The length of the rectangle is twice the width. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #4418 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! Define: \n" ); document.write( "let x=width \n" ); document.write( "therefore length is 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "perimeter is x+x+2x+2x and this equals 150, so 6x=150\r \n" ); document.write( "\n" ); document.write( "--> x = 150/6 \n" ); document.write( "--> x = 25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so width is 25 and length is 50.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |