document.write( "Question 720321: \r
\n" ); document.write( "\n" ); document.write( "If the perimeter of a tennis court is 228 feet and the width is three feet shorter than half of the length, what are the dimensions of the tennis court?
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Algebra.Com's Answer #441772 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
P=2L+2W
\n" ); document.write( "W=L/2-3
\n" ); document.write( "228=2L+2(L/2-3)
\n" ); document.write( "228=2L+L-6
\n" ); document.write( "3L=228+6
\n" ); document.write( "3L=134
\n" ); document.write( "L=234/3
\n" ); document.write( "L=78 ANS. FOR THE LENGTH.
\n" ); document.write( "W=78/2-3=39-3=36 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "228=2*78+2*36
\n" ); document.write( "228=156+72
\n" ); document.write( "228=228
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