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document.write( "There are three consecutive even integers such that 3 times the second is 6 more than the sum of the first and third. Find these integers \n" );
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Algebra.Com's Answer #441766 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE 3 EVEN INTEGERS. \n" ); document.write( "3(X+2)=6+X+(X+4) \n" ); document.write( "3X+6=6+2X+4 \n" ); document.write( "3X-2X=6+4-6 \n" ); document.write( "X=4 ANS. FOR THE SMALLER INTEGER. \n" ); document.write( "4+2=6 ANS. FOR THE MIDDLE INTEGER. \n" ); document.write( "4+4=8 ANS. FOR THE LARGER INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "3*6=6+4+8 \n" ); document.write( "18=18 \n" ); document.write( " |