document.write( "Question 720329: \r
\n" ); document.write( "\n" ); document.write( "how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to obtain a 70% alcohol solution?
\n" ); document.write( "

Algebra.Com's Answer #441765 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.40*80+.30X=.40(70+X)
\n" ); document.write( "32+.30X=28+.40X
\n" ); document.write( ".30X-.40X=28-32
\n" ); document.write( "-.10X=-4
\n" ); document.write( "X=-4/-.10
\n" ); document.write( "X=40 OUNCES OF 30% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".40*80+.30*40=.40(70+40)
\n" ); document.write( "32+12=.40*110
\n" ); document.write( "44=44
\n" ); document.write( "
\n" );