document.write( "Question 720329: \r
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document.write( "how many ounces of a 30% alcohol solution must be mixed with 40 ounces of an 80% alcohol solution to obtain a 70% alcohol solution? \n" );
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Algebra.Com's Answer #441765 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .40*80+.30X=.40(70+X) \n" ); document.write( "32+.30X=28+.40X \n" ); document.write( ".30X-.40X=28-32 \n" ); document.write( "-.10X=-4 \n" ); document.write( "X=-4/-.10 \n" ); document.write( "X=40 OUNCES OF 30% SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".40*80+.30*40=.40(70+40) \n" ); document.write( "32+12=.40*110 \n" ); document.write( "44=44 \n" ); document.write( " |