document.write( "Question 720182: an open tank with square bases is to have a volume of 10 cu. m. the materials for its bottom is to cost P15.00 per square meter and that for the sides P6.00 per square meter . find the most economical dimension for the tank \n" ); document.write( "
Algebra.Com's Answer #441705 by ankor@dixie-net.com(22740)\"\" \"About 
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an open tank with square bases is to have a volume of 10 cu. m.
\n" ); document.write( " the materials for its bottom is to cost P15.00 per square meter and that
\n" ); document.write( " for the sides P6.00 per square meter .
\n" ); document.write( "find the most economical dimension for the tank
\n" ); document.write( ":
\n" ); document.write( "let x = one side of the square base
\n" ); document.write( "let h = the height of the open box
\n" ); document.write( ":
\n" ); document.write( "The volume
\n" ); document.write( "x^2*h = 10
\n" ); document.write( "h = \"10%2Fx%5E2\"
\n" ); document.write( ":
\n" ); document.write( "The surface area cost
\n" ); document.write( "Bottom: 15x^2
\n" ); document.write( "4sides: 6(4xh) = 24xh
\n" ); document.write( ":
\n" ); document.write( "Total cost (c)
\n" ); document.write( "c = 15x^2 + 24xh
\n" ); document.write( "replace h with \"10%2Fx%5E2\"
\n" ); document.write( "c = 15x^2 + 24x*\"10%2Fx%5E2\"
\n" ); document.write( "Cancel
\n" ); document.write( "c = 15x^2 + 24\"10%2Fx\"
\n" ); document.write( "c = 15x^2 + \"240%2Fx\"
\n" ); document.write( "Graphing this would be the easiest way to find minimum cost
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-2%2C+8%2C+-50%2C+300%2C+15x%5E2%2B%28240%2Fx%29%29+\"
\n" ); document.write( "minimum cost when x=2 meters is the side of the square base
\n" ); document.write( "find the height
\n" ); document.write( "h = \"10%2F2%5E2\"
\n" ); document.write( "h = 2.5 meters is the height
\n" ); document.write( "
\n" );