document.write( "Question 720182: an open tank with square bases is to have a volume of 10 cu. m. the materials for its bottom is to cost P15.00 per square meter and that for the sides P6.00 per square meter . find the most economical dimension for the tank \n" ); document.write( "
Algebra.Com's Answer #441705 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! an open tank with square bases is to have a volume of 10 cu. m. \n" ); document.write( " the materials for its bottom is to cost P15.00 per square meter and that \n" ); document.write( " for the sides P6.00 per square meter . \n" ); document.write( "find the most economical dimension for the tank \n" ); document.write( ": \n" ); document.write( "let x = one side of the square base \n" ); document.write( "let h = the height of the open box \n" ); document.write( ": \n" ); document.write( "The volume \n" ); document.write( "x^2*h = 10 \n" ); document.write( "h = \n" ); document.write( ": \n" ); document.write( "The surface area cost \n" ); document.write( "Bottom: 15x^2 \n" ); document.write( "4sides: 6(4xh) = 24xh \n" ); document.write( ": \n" ); document.write( "Total cost (c) \n" ); document.write( "c = 15x^2 + 24xh \n" ); document.write( "replace h with \n" ); document.write( "c = 15x^2 + 24x* \n" ); document.write( "Cancel \n" ); document.write( "c = 15x^2 + 24 \n" ); document.write( "c = 15x^2 + \n" ); document.write( "Graphing this would be the easiest way to find minimum cost \n" ); document.write( " \n" ); document.write( "minimum cost when x=2 meters is the side of the square base \n" ); document.write( "find the height \n" ); document.write( "h = \n" ); document.write( "h = 2.5 meters is the height \n" ); document.write( " |