document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=720107>Question 720107</A>: <I><SPAN STYLE=\"word-break: break-all;\">  My mother is 12 years more than twice my age. After 8 years, my mother’s age will be 20 years less than three times my age. Find my age and my mother’s age.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441663 by </B><A HREF=/tutors/aboutme.mpl?userid=god2012><B>god2012(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=god2012><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=god2012><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'm' be the age of mother and 'k' be the age of the kid.\r<BR>\n" );
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document.write( "Given :  m = 2k + 12 -------eq.1\r<BR>\n" );
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document.write( "After 8 years ,<BR>\n" );
document.write( "m' = m + 8 , k' = k +8<BR>\n" );
document.write( "m' = 3k' - 20  = 3(k + 8) - 20 = 3k + 4 = m + 8\r<BR>\n" );
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document.write( "m = 3k - 4 ------------eq.2\r<BR>\n" );
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document.write( "put eq.2 in eq.1\r<BR>\n" );
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document.write( "3k - 4 = 2k + 12<BR>\n" );
document.write( "k = 16<BR>\n" );
document.write( "m = 44 </SPAN>\n" );
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