document.write( "Question 720085: solve 2sinx-1= 0 for 0 is less than or equal to x less than 2pi \n" ); document.write( "
Algebra.Com's Answer #441645 by god2012(113)![]() ![]() You can put this solution on YOUR website! Given : 2Sinx - 1 = 0\r \n" ); document.write( "\n" ); document.write( "Sinx = 1/2 \n" ); document.write( "x = pi/6 \n" ); document.write( " |