document.write( "Question 720060: A hospital needs 20L of 5% solution. They have 20% solution and 4% solution available. How many L of each 20% and 4% solutions would they have to mix in order to get 20L of 5% solution. \r
\n" ); document.write( "\n" ); document.write( "Here's how I've done so far:
\n" ); document.write( "x+y=20L
\n" ); document.write( ".2x
\n" ); document.write( ".04y
\n" ); document.write( ".05 (x=y)\r
\n" ); document.write( "\n" ); document.write( ".2x+.04y=.05 (x+y)\r
\n" ); document.write( "\n" ); document.write( "(I'm not sure if I'm even going the right direction here and this is where I stop knowing what to do) \n" ); document.write( "
Algebra.Com's Answer #441635 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
percent ---------------- quantity
\n" ); document.write( "Solution I 20.00% ---------------- x liters
\n" ); document.write( "Solution II 4.00% ------ 20 - x liters
\n" ); document.write( "Mixture 5.00% ---------------- 20
\n" ); document.write( " 20
\n" ); document.write( "20.00% x + 4.00% ( 20 - x ) = 5.00% * 20
\n" ); document.write( "20 x + 4 ( 20 - x ) = 100
\n" ); document.write( "20 x + 80 - 4 x = 100
\n" ); document.write( "20 x - 4 x = 100 - -80
\n" ); document.write( "16 x = 20
\n" ); document.write( "/ 16
\n" ); document.write( " x = 1.25 liters 20.00% Solution
\n" ); document.write( " 18.75 liters 4.00% solution
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\n" ); document.write( "m.ananth@hotmail.ca
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