document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719979>Question 719979</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A chemist has two alloys, one of which is 15% gold and 15% lead and the other which is 40% gold and 30% lead. How many grams of each of the two alloys should be used to make an alloy that contains 80.5 g of gold and 76.5 g of lead?\r<BR>\n" );
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document.write( "_____ g (first alloy)<BR>\n" );
document.write( "_____ g (second alloy) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441627 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Summary of given information:<BR>\n" );
document.write( "First alloy: 15% Gold, 15% Lead.<BR>\n" );
document.write( "Second alloy: 40% Gold, 30% Lead.<BR>\n" );
document.write( "WANT NEW ALLOY containing 80.5 grams Gold and 76.5 grams Lead.\r<BR>\n" );
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document.write( "Let x = grams of first alloy<BR>\n" );
document.write( "Let y = grams of second alloy\r<BR>\n" );
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document.write( "Account for Gold:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.15x%2B0.40y=80.5+ ALIGN=MIDDLE  ALT=\"0.15x%2B0.40y=80.5+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Account for Lead:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.15x%2B0.30y=76.5 ALIGN=MIDDLE  ALT=\"0.15x%2B0.30y=76.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Those two, when multiplied by 100 and then divided by 5 give the equivalent system,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%283x%2B8y=1610%29 ALIGN=MIDDLE  ALT=\"highlight%283x%2B8y=1610%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%283x%2B6y=1530%29 ALIGN=MIDDLE  ALT=\"highlight%283x%2B6y=1530%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "In that form, the second equation can be subtracted from the first equation and the result solved for y, giving the grams of the \"second alloy\" to use.  Next, use either equation of this system to find the value of x, the \"first alloy\" to use.\r<BR>\n" );
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