document.write( "Question 720020: On Monday, Amy cycled 24 miles in 2 hours at a constant rate. On Tuesday, she cycled at an average of 3 mph faster. What was her rate on Tuesday?\r
\n" ); document.write( "\n" ); document.write( "I tried 24/2= 12
\n" ); document.write( "So 24+3=27 and divide by 2 would equal 13.5.\r
\n" ); document.write( "\n" ); document.write( "My choices are:
\n" ); document.write( "A. 3 mph\r
\n" ); document.write( "\n" ); document.write( "B. 15 mph\r
\n" ); document.write( "\n" ); document.write( "C. 30 mph\r
\n" ); document.write( "\n" ); document.write( "D. 120 mph
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Algebra.Com's Answer #441623 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
On Monday, Amy cycled 24 miles in 2 hours at a constant rate. On Tuesday, she cycled at an average of 3 mph faster. What was her rate on Tuesday?
\n" ); document.write( "I tried 24 miles/2 hrs= 12 mph
\n" ); document.write( "So rate on Tuesday = 12+3=15 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "My choices are:
\n" ); document.write( "A. 3 mph
\n" ); document.write( "B. 15 mph
\n" ); document.write( "C. 30 mph
\n" ); document.write( "D. 120 mph
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