document.write( "Question 720020: On Monday, Amy cycled 24 miles in 2 hours at a constant rate. On Tuesday, she cycled at an average of 3 mph faster. What was her rate on Tuesday?\r
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document.write( "I tried 24/2= 12
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document.write( "So 24+3=27 and divide by 2 would equal 13.5.\r
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document.write( "My choices are:
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document.write( "A. 3 mph\r
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document.write( "B. 15 mph\r
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document.write( "C. 30 mph\r
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document.write( "D. 120 mph
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Algebra.Com's Answer #441623 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! On Monday, Amy cycled 24 miles in 2 hours at a constant rate. On Tuesday, she cycled at an average of 3 mph faster. What was her rate on Tuesday? \n" ); document.write( "I tried 24 miles/2 hrs= 12 mph \n" ); document.write( "So rate on Tuesday = 12+3=15 mph \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------------- \n" ); document.write( "My choices are: \n" ); document.write( "A. 3 mph \n" ); document.write( "B. 15 mph \n" ); document.write( "C. 30 mph \n" ); document.write( "D. 120 mph \n" ); document.write( " \n" ); document.write( " |