document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=720017>Question 720017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two positive consecutive even integers whose product is 8 more than 5 times the larger integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441622 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 2*n be the first even integer. Then the next even integer is 2*n+2. 8 more than 5 times the larger integer is 5*(2*n+2)+8. As this is the product of the consecutive integers we have that<BR>\n" );
document.write( "(2*n)*(2*n+2)=5*(2*n+2)+8<BR>\n" );
document.write( "2^2*n^2+4*n=10*n+10+8<BR>\n" );
document.write( "2^2*n^2-6*n-18=0<BR>\n" );
document.write( "2*n^2-3*n-9=0<BR>\n" );
document.write( "Let's try to factor this expression\r<BR>\n" );
document.write( "\n" );
document.write( "(2*n+3)*(n-3)=0<BR>\n" );
document.write( "we get n=-3/2 and n=3. We must want the integer 3 so our even integers must be 6 and 8. Check that they work in the first equation.  </SPAN>\n" );
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